20x^2+36x=-7

Solution for 20x^2+36x=-7 equation:

20x^2+36x=-7

We move all terms to the left:

20x^2+36x-(-7)=0

We add all the numbers together, and all the variables

20x^2+36x+7=0

a = 20; b = 36; c = +7;
Δ = b2-4ac
Δ = 362-4·20·7
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{46}}{2*20}=\frac{-36-4\sqrt{46}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{46}}{2*20}=\frac{-36+4\sqrt{46}}{40}
$